wer-weiss-was.de
Logarithmus
Wissenschaft
Physik
Oliver_a32c43
4. Dezember 2003 um 17:02
2
a^(log_a (x^y)) = a^(y * log_a x)
a^(log_a (x^y)) = x^y = (a^(log_a (x)))^y = a^(y * log_a x)